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Lead sulfide is PbS and not PbS2 because lead has a +2 oxidation state and sulfur has a -2 oxidation state. When these two elements combine, they form a 1:1 ratio of lead to sulfur atoms, resulting in the chemical formula PbS. If lead were to form a compound with sulfur in a 2:1 ratio, it would result in PbS2, but this is not the case for lead sulfide. Therefore, the correct chemical formula for lead sulfide is PbS. **

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To calculate the pH of a PBS buffer, you would first need to know the concentrations of the components of the buffer: sodium chloride, sodium phosphate, and potassium chloride. Then, you would use the Henderson-Hasselbalch equation, pH = pKa + log([A-]/[HA]), where pKa is the acid dissociation constant of the weak acid in the buffer, [A-] is the concentration of the conjugate base, and [HA] is the concentration of the weak acid. By plugging in the appropriate values for the concentrations and pKa, you can calculate the pH of the PBS buffer. **

To calculate the grams of lead and sulfur needed to produce 10 g of lead sulfide (PbS), we first need to find the molar mass of PbS. The molar mass of Pb is 207.2 g/mol, and the molar mass of S is 32.1 g/mol. Adding these together gives us the molar mass of PbS as 239.3 g/mol. Next, we can use the molar ratio of lead to sulfur in PbS, which is 1:1. This means that for every 1 gram of lead, we need 1 gram of sulfur. Therefore, to produce 10 g of PbS, we need 5 g of lead and 5 g of sulfur. So, 5 g of lead and 5 g of sulfur must be weighed to produce 10 g of lead sulfide. **

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To calculate the amount of lead and sulfur needed to produce 10 g of lead sulfide (PbS), we need to consider the molar ratio of lead to sulfur in PbS, which is 1:1. The molar mass of lead is 207.2 g/mol and sulfur is 32.1 g/mol. First, calculate the molar mass of PbS: 207.2 g/mol (Pb) + 32.1 g/mol (S) = 239.3 g/mol (PbS) Next, calculate the number of moles of PbS in 10 g: 10 g / 239.3 g/mol = 0.0418 mol Since the molar ratio of Pb to S is 1:1, the number of moles of lead and sulfur needed is also 0.0418 mol. Finally, calculate the mass of lead and sulfur needed: Lead: 0.0418 mol x **

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